import re
from urllib import urlopen
uniqueBanList = []
totalBanList = []
url = 'http://74.63.239.234/banlist.txt'
import itertools
import operator
 
def most_common(L):
  # get an iterable of (item, iterable) pairs
  SL = sorted((x, i) for i, x in enumerate(L))
  # print 'SL:', SL
  groups = itertools.groupby(SL, key=operator.itemgetter(0))
  # auxiliary function to get "quality" for an item
  def _auxfun(g):
    item, iterable = g
    count = 0
    five = 5
    min_index = len(L)
    for _, where in iterable:
      count += 1
      min_index = min(min_index, where)
    if count >= five:
        print 'item %r, count %r, minind %r' % (item, count, min_index)
    return count, -min_index
  # pick the highest-count/earliest item
  return max(groups, key=_auxfun)[0]
 
def num_groups(regex, url):
    webpage = urlopen(url).read()
    m = re.findall(regex, webpage)
    return m
 
if __name__ == "__main__":
    for i in num_groups(r'(\bSTEAM_[0-1]:[0-1]:\d+\b).*', url):
        totalBanList.append(i)
        if i not in uniqueBanList: uniqueBanList.append(i)
    print "There have been "+str(len(totalBanList))+ " total bans and "+str(len(uniqueBanList))+" unique people banned since the beginning of time on Noobonic Plague."
    z = raw_input("Do you want to see the list of most-banned people? 1 for yes, 0 for no. > ")
    if z == r'1':
        print most_common(totalBanList)
    else:
        quit()