Title:           [Java] warning, retarded code ahead
Author:          rylai
Pastebin link:   http://pastebin.com/d4PpAAPK
First Edit:      Wednesday 13th of March 2013 06:36:49 PM CDT
Last Edit:       Wednesday 13th of March 2013 06:36:49 PM CDT

        private static String findMiddleString(ArrayList<String> compareHolder) {
                String finalResult = new String();
                if(compareHolder.get(0).compareToIgnoreCase(compareHolder.get(1)) > 0) { // if 0 is lexicographically after 1, then...
                        if(compareHolder.get(0).compareToIgnoreCase(compareHolder.get(2)) < 0)  { // get(0) is the middle, yay, this was easy
                                return compareHolder.get(0); } else { // get(0) is NOT the middle, therefore one of the other two must be
                                        return(compareHolder.get(1)); // get(0) is not the middle but is greater than get(1), so get(1) is the middle
                                        }              
                } else if(compareHolder.get(0).compareToIgnoreCase(compareHolder.get(2)) > 0) { // if 0 is l16y before 1 and l16y after 2, then it's the mid
                       
                }
                return finalResult;